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ap dp

ap dp

AP & DP Brackets Bonus Guide ap dp Given: Seg AC and seg BD intersect each other in point P and AP CP BP DP AP CP = BP DP To prove: ∆ABP ~ ∆CDP Proof: In ∆ABP and ∆CDP, approval slip Click here:point_up_2:to get an answer to your question :writing_hand:abcd is a quadrilateral and ap and dp are bisectors of angle a

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